High-Power target simulation

DarthNul · May 17, 2014, 07:40 PM

I going to set up a spot at home for dry fire practice. I'm wondering if anybody has already done the math for this...

What size "black dot" do I need at 25 feet, to look like the black of an SR target at 200 yards?

kbuilta · May 17, 2014, 10:45 PM

If I got the SR target right, the 9-ring is the outer black diameter and is 13 inches in DIA. Scale that from 200 yds back to 8.3 yds (25 ft) and 13 inches becomes 0.542 inches. Hope that helps.

DarthNul · May 18, 2014, 01:05 AM

Thanks!

jjbduke2004 · May 18, 2014, 12:43 PM

Some of these may help you. The spreadsheet will allow you to compute reduced target sizes.
http://www.ray-vin.com/tech/targets/targetlist.htm

My SCATT electronic trainer has a target generator program that can scale targets. I can email you a 8.5x11 printable PDF of the 200 yd SR scaled to 7.62 meters (25 ft). Just PM me your email address.

Jimro · May 18, 2014, 01:57 PM

13 inches at 200 yards = 6.5 MOA aiming black.

6.5 MOA times 1/4 inches (one MOA at 25 yards) = 1.625 inches, or 1 and 5/8ths of an inch. 0.542 inches should be about the diameter of the 10 ring inside the aiming black.

Jimro

May 17, 2014, 07:40 PM	#1
DarthNul Senior Member Join Date: December 21, 2010 Location: Minnesota Posts: 288	High-Power target simulation I going to set up a spot at home for dry fire practice. I'm wondering if anybody has already done the math for this... What size "black dot" do I need at 25 feet, to look like the black of an SR target at 200 yards? __________________ The most feared gun control law proposal: Require buyers to register all gun purchases with their wives

May 18, 2014, 01:05 AM	#3
DarthNul Senior Member Join Date: December 21, 2010 Location: Minnesota Posts: 288	Thanks! __________________ The most feared gun control law proposal: Require buyers to register all gun purchases with their wives

May 18, 2014, 01:57 PM	#5
Jimro Senior Member Join Date: October 18, 2006 Posts: 7,097	13 inches at 200 yards = 6.5 MOA aiming black. 6.5 MOA times 1/4 inches (one MOA at 25 yards) = 1.625 inches, or 1 and 5/8ths of an inch. 0.542 inches should be about the diameter of the 10 ring inside the aiming black. Jimro __________________ Machine guns are awesome until you have to carry one.

May 17, 2014, 10:45 PM	#2
kbuilta Junior Member Join Date: December 15, 2012 Posts: 12	If I got the SR target right, the 9-ring is the outer black diameter and is 13 inches in DIA. Scale that from 200 yds back to 8.3 yds (25 ft) and 13 inches becomes 0.542 inches. Hope that helps.

May 18, 2014, 12:43 PM	#4
jjbduke2004 Junior Member Join Date: May 17, 2009 Posts: 8	Some of these may help you. The spreadsheet will allow you to compute reduced target sizes. http://www.ray-vin.com/tech/targets/targetlist.htm My SCATT electronic trainer has a target generator program that can scale targets. I can email you a 8.5x11 printable PDF of the 200 yd SR scaled to 7.62 meters (25 ft). Just PM me your email address.