MOA definition - Page 2

Buzzcook · December 20, 2011, 07:39 PM

I don't think I've seen an older thread resurrected.
Still pretty useful info.

(*_*) · December 24, 2011, 07:34 PM

Use the name that all the other industry's use and info is easy to find...
http://en.wikipedia.org/wiki/Minute_of_arc

Chuck Dye · December 25, 2011, 12:33 PM

Quote:

Originally Posted by brickeyee

You can get the correct answer by dividing the group size by 2, computing the angle,and then doubling it.
MOA is not a perpendicular concept, but a circular measurement.

Using my ancient H-P 15C, that 1.5 inch group yields 1.432394405, twice a .75 incher produces 1.432394467, a 4.3284x10^-06% difference. I can live with the error.

brickeyee · December 25, 2011, 03:17 PM

Quote:

Using my ancient H-P 15C, that 1.5 inch group yields 1.432394405, twice a .75 incher produces 1.432394467, a 4.3284x10-06% difference. I can live with the error

.

Fine for you, but it is still wrong.
How about telling folks the correct way and letting them decide on the error they are wiling to put up with?

December 24, 2011, 07:34 PM	#27
(_) Senior Member Join Date: November 20, 2011 Location: AL Posts: 160	Use the name that all the other industry's use and info is easy to find... http://en.wikipedia.org/wiki/Minute_of_arc __________________ Though i did not know the place, i set out for the land of my dreams. Having arrived at the land of my dreams, i found i did not know the place.

December 20, 2011, 07:39 PM	#26
Buzzcook Senior Member Join Date: November 29, 2007 Location: Everett, WA Posts: 6,126	I don't think I've seen an older thread resurrected. Still pretty useful info.