The Firing Line Forums - View Single Post - How do you figure a bullet's force on impact?

Slamfire · May 25, 2008, 08:01 AM

I recall that it is momentum (M * V) that is conserved in a collision, not Kinetic Energy (M * V * V).

It is far easier to increase KE a lot than it is to increase ME a little. Shill gunwriters have to write articles selling products, and it is far easier to shill an increase in KE. Just an increase in 10 fps will increase KE by 100. An increase in 100 fps will increase KE by 1000. Shills just make that increase seem galactic by proportions.

This is the basis for the sales campaign for the 327 Federal. Drop bullet weight, increase velocity, and claim you have something as effective as a 357.

You would think after reading all the garbage put out by shill gunwriters that anything under 3000 fps is totally ineffective, but 16 inch Battleship shells flew around 2000 fps. I heard the New Jersey’s shells made 60 foot divots in the soil of Lebanon.

May 25, 2008, 08:01 AM	#17
Slamfire Senior Member Join Date: May 27, 2007 Posts: 5,261	I recall that it is momentum (M * V) that is conserved in a collision, not Kinetic Energy (M * V * V). It is far easier to increase KE a lot than it is to increase ME a little. Shill gunwriters have to write articles selling products, and it is far easier to shill an increase in KE. Just an increase in 10 fps will increase KE by 100. An increase in 100 fps will increase KE by 1000. Shills just make that increase seem galactic by proportions. This is the basis for the sales campaign for the 327 Federal. Drop bullet weight, increase velocity, and claim you have something as effective as a 357. You would think after reading all the garbage put out by shill gunwriters that anything under 3000 fps is totally ineffective, but 16 inch Battleship shells flew around 2000 fps. I heard the New Jersey’s shells made 60 foot divots in the soil of Lebanon.