March 16, 2009, 01:45 PM  #1 
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If a 30 MM set of rings comes with .10" inserts, would that be equivelant to making the rings canted to 10 MOA?

March 16, 2009, 02:37 PM  #2 
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Depends on how far apart they are set.
1 MOA approx equals 1" at 100 yards. that means .010 inches (one one hundredth of an inch) approx equals 1 MOA at 1 yard. We will assume that your rings are space 6" apart, which is 1/6 of a yard. So a .010" offset will mean a difference of approx 6 MOA. If your rings are 5" apart then the difference is about 7 MOA. The math is 1 MOA divided by the fraction of the yard distance (which is the same as multiplied by the inverse). 1 divided by 1/6 equals 6, (6" equals 1/6 of a yard, 5" approx equals 1/7.2 of a yard) Simple math, it could be wrong but I hope it helps. If you use two inserts (one in each ring) double the MOA gained. Just remember to put the rear insert thick on the bottom, and the front insert thick on the top. Jimro
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Machine guns are awesome until you have to carry one. Last edited by Jimro; March 16, 2009 at 02:43 PM. Reason: unsure of my trig... 
March 16, 2009, 06:51 PM  #3  
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March 16, 2009, 10:49 PM  #4  
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Scorch,
The full quote is this: Quote:
Jimro
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Machine guns are awesome until you have to carry one. 

March 17, 2009, 10:15 AM  #5 
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Bryce,
Checked my math with the guys over at snipersparadise, and the easy math is this. The TAN of the angle you wish to achieve (20 MOA) multiplied by the distance between the scope mounts, center to center, (3.625) equals the distance the rear mount needs to come up (.021), to check this you can merely change the distance number to a yardage in inches ie 3600 for 100 yds which comes out to 20.94" or approximately 20 MOA. But you have a Ruger Hawkeye and I don't know the exact center to center distance between your rings. So what you need to do is measure the distance between the ring centers, and use this formula. Tan(X)= (shim offset)/(distance between ring centers) That means InverseTan(shim offset/distance between rings) = X X is in degrees so multiply by 60 to turn it into minutes. For example, InverseTan(0.010"/4") = 0.1432. 0.1432x60= 8.6 MOA You can also play around with the formula to figure out how much shimming you need to get the MOA you want. Say you want 15 MOA, (15 minutes is one quarter of a degree, 15/60=0.25). Tan(.25) = X/(distance between rings). Lets assume 5 inches this between rings. Tan(.25)x5"= 0.0218" of offset. I hope this gives you the tools you need to achieve the effect you desire. Jimro
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Machine guns are awesome until you have to carry one. 
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