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Old December 20, 2011, 07:39 PM   #26
Buzzcook
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I don't think I've seen an older thread resurrected.
Still pretty useful info.
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Old December 24, 2011, 07:34 PM   #27
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Use the name that all the other industry's use and info is easy to find...
http://en.wikipedia.org/wiki/Minute_of_arc
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Old December 25, 2011, 12:33 PM   #28
Chuck Dye
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Quote:
Originally Posted by brickeyee
You can get the correct answer by dividing the group size by 2, computing the angle,and then doubling it.
MOA is not a perpendicular concept, but a circular measurement.
Using my ancient H-P 15C, that 1.5 inch group yields 1.432394405, twice a .75 incher produces 1.432394467, a 4.3284x10-06% difference. I can live with the error.
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Old December 25, 2011, 03:17 PM   #29
brickeyee
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Quote:
Using my ancient H-P 15C, that 1.5 inch group yields 1.432394405, twice a .75 incher produces 1.432394467, a 4.3284x10-06% difference. I can live with the error
.

Fine for you, but it is still wrong.
How about telling folks the correct way and letting them decide on the error they are wiling to put up with?
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