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kraigwy · September 5, 2012, 10:05 PM

Might add a note to your angle fire page.

As you show, the actual distance is line of sight distance times the cosine of the angle is the actual distance to the target.

BUT.

You still have to account for the wind the full line of sight distance.

An example:

Line of sight distance being 600 yards, at 30 degrees. You cosine would be .87 giving you the distance of 522 yards. Meaning your elevation is set for 522 instead of 600.

But the wind effects the bullet for the full 600 yards.

Good job.

Just Saying.

September 5, 2012, 10:05 PM	#2
kraigwy Senior Member Join Date: June 16, 2008 Location: Wyoming Posts: 11,061	Might add a note to your angle fire page. As you show, the actual distance is line of sight distance times the cosine of the angle is the actual distance to the target. BUT. You still have to account for the wind the full line of sight distance. An example: Line of sight distance being 600 yards, at 30 degrees. You cosine would be .87 giving you the distance of 522 yards. Meaning your elevation is set for 522 instead of 600. But the wind effects the bullet for the full 600 yards. Good job. Just Saying. __________________ Kraig Stuart CPT USAR Ret USAMU Sniper School Distinguished Rifle Badge 1071