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Old November 17, 2012, 06:18 AM   #156
OldMarksman
Senior Member
 
Join Date: June 8, 2008
Posts: 1,872
Quote:
Posted by barnbwt: The odds of getting two shots of six are:
.3*.3 = .09 (0 miss)
.3*.3*.7 = .063*2 (1 misses, 2 ways)
.3*.3*.7*.7 = .0441*3 (2 misses, 3 ways)
.3*.3*.7*.7*.7 = .0309*4 (3 misses, 4 ways)
.3*.3*.7*.7*.7*.7 = .0216*5 (4 misses, 5 ways)
Grand Total: 58% chance of stopping one guy with 2 of six bullets
That's the idea.

The link in Post #36 gives the same result, and allows one to vary that hit rate and the number of rounds, and to consider the possibility of a second attacker.

The graphs shown in Post #10 of that link are eye-openers.

Last edited by OldMarksman; November 17, 2012 at 06:27 AM.
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