Quote:
Posted by barnbwt: The odds of getting two shots of six are:
.3*.3 = .09 (0 miss)
.3*.3*.7 = .063*2 (1 misses, 2 ways)
.3*.3*.7*.7 = .0441*3 (2 misses, 3 ways)
.3*.3*.7*.7*.7 = .0309*4 (3 misses, 4 ways)
.3*.3*.7*.7*.7*.7 = .0216*5 (4 misses, 5 ways)
Grand Total: 58% chance of stopping one guy with 2 of six bullets

That's the idea.
The link in Post #36 gives the same result, and allows one to vary that hit rate and the number of rounds, and to consider the possibility of a second attacker.
The graphs shown in Post #10 of that link are eyeopeners.