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landcruzr
November 22, 2009, 09:33 PM
Can someone explain to me what this score would mean in a .22 rifle match:
539 (18x)
and how you go about calculating scores?
If I sound confused- its because I am :)

mapsjanhere
November 22, 2009, 10:11 PM
60 shots on a target with rings 1 - 10. This gives you the 539 (on average a 9). The 10 ring has an inner smaller ring, the x ring. It's used to break ties, depending on how many of the 10's were "perfect". The x ring usually means that the bullet hit the dead center of the target at least partially. So, in your example, the guy had 18 x shots (10's dead center).
But the x shots are only the tie breaker, 600 points no x beat 599 (59x).

LHB1
November 22, 2009, 11:26 PM
When shooting at a numbered bullseye target, a shot scores the highest numbered ring that it touches. Example: if a bullet hole touches the 10 ring, then it counts as a 10 even though most of the bullet hole is in the 9 ring. A typical target may only have a few numbered scoring rings such as 10, 9, 8, and 7. Any shots that hit outside all numbered rings are misses and count as zero.

darkgael
November 23, 2009, 06:27 AM
Interestingly enough, it is not uncommon at a prone rifle match involving elite shooters to have perfect 600/1200/1800/2400 scores shot by more than one shooter and the match will be decided on X-counts.
Pete